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	Common: Remove redundant masking in BitField
For the signed case, the shifts already remove the rest of the value, so ANDing by the mask is redundant.
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		|  | @ -160,7 +160,7 @@ public: | |||
|         if (std::numeric_limits<T>::is_signed) | ||||
|         { | ||||
|             std::size_t shift = 8 * sizeof(T)-bits; | ||||
|             return (T)(((storage & GetMask()) << (shift - position)) >> shift); | ||||
|             return (T)((storage << (shift - position)) >> shift); | ||||
|         } | ||||
|         else | ||||
|         { | ||||
|  |  | |||
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