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	string_util: Remove unnecessary std::string instance in TabsToSpaces()
We can just use the variant of std::string's replace() function that can replace an occurrence with N copies of the same character, eliminating the need to allocate a std::string containing a buffer of spaces.
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					 2 changed files with 7 additions and 8 deletions
				
			
		|  | @ -236,15 +236,14 @@ void SplitString(const std::string& str, const char delim, std::vector<std::stri | ||||||
|     output.pop_back(); |     output.pop_back(); | ||||||
| } | } | ||||||
| 
 | 
 | ||||||
| std::string TabsToSpaces(int tab_size, const std::string& in) { | std::string TabsToSpaces(int tab_size, std::string in) { | ||||||
|     const std::string spaces(tab_size, ' '); |  | ||||||
|     std::string out(in); |  | ||||||
| 
 |  | ||||||
|     size_t i = 0; |     size_t i = 0; | ||||||
|     while (out.npos != (i = out.find('\t'))) |  | ||||||
|         out.replace(i, 1, spaces); |  | ||||||
| 
 | 
 | ||||||
|     return out; |     while ((i = in.find('\t')) != std::string::npos) { | ||||||
|  |         in.replace(i, 1, tab_size, ' '); | ||||||
|  |     } | ||||||
|  | 
 | ||||||
|  |     return in; | ||||||
| } | } | ||||||
| 
 | 
 | ||||||
| std::string ReplaceAll(std::string result, const std::string& src, const std::string& dest) { | std::string ReplaceAll(std::string result, const std::string& src, const std::string& dest) { | ||||||
|  |  | ||||||
|  | @ -69,7 +69,7 @@ static bool TryParse(const std::string& str, N* const output) { | ||||||
|         return false; |         return false; | ||||||
| } | } | ||||||
| 
 | 
 | ||||||
| std::string TabsToSpaces(int tab_size, const std::string& in); | std::string TabsToSpaces(int tab_size, std::string in); | ||||||
| 
 | 
 | ||||||
| void SplitString(const std::string& str, char delim, std::vector<std::string>& output); | void SplitString(const std::string& str, char delim, std::vector<std::string>& output); | ||||||
| 
 | 
 | ||||||
|  |  | ||||||
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